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Logarithm Question
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Thread: Logarithm Question

  1. 07-05-2007, 15:46 #1
    Zero
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    Default Logarithm Question

    Im stuck on an equation. Anyone good at Logs?

    [Q] Solve: Log2X + Log4X = 2

    I got to the next bit with the change of base rule:

    (Log10X /     Log102) + (Log10X / Log104) = 2

    Now Im stuck.
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  2. 07-05-2007, 15:48 #2
    Voodookid
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    you can write the sum of two logs as the multiplication of the 2x and the 4x.

    taking the antilog of both sides

    (2x)*(4x) = antilog of 2
    8x^2 = 100
    x = 3.5355
    e: vdk[at]theasianplace[dot]net
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  3. 07-05-2007, 15:56 #3
    Zero
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    Aha....so the change of base was going down the wrong way.

    Cheers for that voodoo!
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  4. 07-05-2007, 15:59 #4
    Voodookid
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    no worries!
    e: vdk[at]theasianplace[dot]net
    MAAAA, THE MEATLOAF..... FUCK!

    "I'm not heterosexual, homosexual, or bisexual. I'm just sexual. NO. MOTHERF*CKING. PREFIX.\"
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  5. 09-05-2007, 23:49 #5
    Zero
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    Right, Voodoo or anyone else good at le mathmetique, I am in another Log predicament.

    Question:

    "Solve the simulatanoues equations leaving your answer as an exact fraction":

    [E1] 8Y = 42X+3
    [E2] Log2Y = log2X + 4

    What voodoo stated before, taking the anitlogs: I dont know if this is the right direction to take but, I took the anti logs of [E2]. That left me with:

    Y = X + 4

    Then I subsituted this "X + 4" as "Y" into [E1] so I got:

    8X+4 = 42X+3

    Therefore this gives:

    (84)(X4) = 42X+3


    And Now Im Stuck. Help
    Last edited by Zero; 09-05-2007 at 23:49.
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  6. 09-05-2007, 23:52 #6
    Zero
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    Oh bluddy hell, the indices didnt come out right.!!

    Leave it peeps.
    Last edited by Zero; 09-05-2007 at 23:53.
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  7. 09-05-2007, 23:53 #7
    AmericanBoi
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    from wat i am seeing cant u just take the X's on one side and solve for X?????





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  8. 09-05-2007, 23:56 #8
    Zero
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    Quote Originally Posted by AmericanBoi
    from wat i am seeing cant u just take the X's on one side and solve for X?????
    No, theres one problem:

    In [E1] the "Y" is the power raised to 8.

    and in [E2] "2X + 3" is the power raised to 4.

    So it makes life difficult.
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  9. 09-05-2007, 23:57 #9
    AmericanBoi
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    u can get an online calculator to do the powers of such equations if u dont have to show the work use that. but i am still confused as to how the original equation looks like can u put up a pic i can help u prolly.





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  10. 10-05-2007, 00:14 #10
    Zero
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    Help me please.
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  11. 10-05-2007, 00:15 #11
    Zero
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    The working under the [E1] and [E2] is mine. I dunno if that is right.
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  12. 10-05-2007, 00:17 #12
    AmericanBoi
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    are u on msn?





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  13. 10-05-2007, 00:18 #13
    desimack
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    LOL I'm keeping out of this one.

    I'm glad I didn't take maths any further!
    I mean nobody likes me, everybody hates me, keep that shit coming, watch how much stronger it makes me!

    Its not like I idolize this Machiavelli I idolize that type of thinking where you do what evers gonna make you achieve ur goals
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  14. 10-05-2007, 00:21 #14
    AmericanBoi
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    shit man i wasnt allowed log tables in ma exams i dont know how i solved log problems, but i was allowed calculators





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  15. 10-05-2007, 00:24 #15
    desimack
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    We touched on this in college it was a nightmare to do!
    I mean nobody likes me, everybody hates me, keep that shit coming, watch how much stronger it makes me!

    Its not like I idolize this Machiavelli I idolize that type of thinking where you do what evers gonna make you achieve ur goals
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